Question

liquid nitrogen boils at -195.8°c. express the boiling point of liquid nitrogen in kelvin.
-469.0 k
-77.4 k
all temperatures are 0 k on the kelvin scale
77.4 k
469.0 k

Explanation:

Step1: Recall the formula to convert Celsius to Kelvin

The formula to convert temperature from Celsius ($^\circ$C) to Kelvin (K) is $K = ^\circ C + 273.15$.

Step2: Substitute the given Celsius temperature into the formula

We are given the boiling point of liquid nitrogen as $- 195.8^\circ$C. Substitute this value into the formula: $K=-195.8 + 273.15$.

Step3: Calculate the result

$-195.8+273.15 = 77.35\approx77.4$ K.

Answer:

77.4 K (corresponding to the option "77.4 K")