Question

listed below are amounts (in millions of dollars) collected from parking meters by a security company in a certain city. a larger data set was used to convict 5 members of the company of grand larceny. find the mean and median for each of the two samples and then compare the two sets of results. do the limited data listed here show evidence of stealing by the security companys employees? security company: 1.6 1.4 1.6 1.4 1.7 1.3 1.8 1.3 1.3 1.5 other companies: 1.6 2.1 1.8 2.2 1.8 1.9 2.1 2.2 2.2 2.3 find the means. the mean for the security company is $\square$ million and the mean for the other companies is $\square$ million (type integers or decimals rounded to two decimal places as needed.)

Explanation:

Step1: Calculate mean for security company

The formula for the mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$. For the security company, $n = 10$, and $\sum x_{i}=1.6+1.4+1.6+1.4+1.7+1.3+1.8+1.3+1.3+1.5 = 15.2$. So, $\bar{x}_{1}=\frac{15.2}{10}=1.52$.

Step2: Calculate mean for other companies

For the other - companies, $n = 10$, and $\sum x_{i}=1.6+2.1+1.8+2.2+1.8+1.9+2.1+2.2+2.2+2.3 = 20.2$. So, $\bar{x}_{2}=\frac{20.2}{10}=2.02$.

Answer:

The mean for the security company is $\$1.52$ million and the mean for the other companies is $\$2.02$ million.