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Question
7 - m1 - tb - lesson 11
- consider the given rectangle.
3\frac{1}{2} inches
1\frac{3}{4} inches
a. find the area of the rectangle.
b. find the perimeter of the rectangle.
Step1: Convert mixed - numbers to improper fractions
$3\frac{1}{2}=\frac{3\times2 + 1}{2}=\frac{7}{2}$ and $1\frac{3}{4}=\frac{1\times4+3}{4}=\frac{7}{4}$
Step2: Calculate the area of the rectangle
The area formula of a rectangle is $A = l\times w$. So $A=\frac{7}{2}\times\frac{7}{4}=\frac{49}{8}=6\frac{1}{8}$ square inches.
Step3: Calculate the perimeter of the rectangle
The perimeter formula of a rectangle is $P = 2(l + w)$. First, $l + w=\frac{7}{2}+\frac{7}{4}=\frac{14 + 7}{4}=\frac{21}{4}$. Then $P = 2\times\frac{21}{4}=\frac{21}{2}=10\frac{1}{2}$ inches.
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a. $6\frac{1}{8}$ square inches
b. $10\frac{1}{2}$ inches