Question

match each expression in column a with the expression in column b that has the same value.
$-10 + (-7)$ \t\t\t\t a. $-10 - 7$
$-10 + 7$ \t\t\t\t\t b. $-15 \div (-6)$
$15 \cdot \frac{1}{6}$ \t\t\t c. $-10 - (-7)$
$15 \div (-6)$ \t\t\t\t d. $-15 \cdot \frac{1}{6}$

Explanation:

Step1: Evaluate $-10 + (-7)$

$ -10 + (-7) = -17 $

Step2: Evaluate option a: $-10 -7$

$ -10 -7 = -17 $

Step3: Evaluate $-10 +7$

$ -10 +7 = -3 $

Step4: Evaluate option c: $-10 - (-7)$

$ -10 - (-7) = -10 +7 = -3 $

Step5: Evaluate $15 \cdot \frac{1}{6}$

$ 15 \cdot \frac{1}{6} = \frac{15}{6} = \frac{5}{2} $

Step6: Evaluate option b: $-15 \div (-6)$

$ -15 \div (-6) = \frac{-15}{-6} = \frac{15}{6} = \frac{5}{2} $

Step7: Evaluate $15 \div (-6)$

$ 15 \div (-6) = -\frac{15}{6} = -\frac{5}{2} $

Step8: Evaluate option d: $-15 \cdot \frac{1}{6}$

$ -15 \cdot \frac{1}{6} = -\frac{15}{6} = -\frac{5}{2} $

Answer:

$-10 + (-7)$ matches a. $-10 - 7$
$-10 + 7$ matches c. $-10 - (-7)$
$15 \cdot \frac{1}{6}$ matches b. $-15 \div (-6)$
$15 \div (-6)$ matches d. $-15 \cdot \frac{1}{6}$