Question

match the function written in standard notation on the left with the same function written in function notation on the right.
press to hear the question read out loud.

$y = \frac{3}{4}x + 12$

a. $f(x) = \frac{4}{3}x - 16$

$y = -2x - 6$

b. $f(x) = -2x - 6$

$y = \frac{4}{3}x - 16$

c. $f(x) = -\frac{1}{2}x - 3$

$y = -\frac{1}{2}x - 3$

d. $f(x) = \frac{3}{4}x + 12$

Explanation:

Step1: Match first standard function

In function notation, $y$ is replaced with $f(x)$. For $y=\frac{3}{4}x+12$, the matching function is $f(x)=\frac{3}{4}x+12$.

Step2: Match second standard function

For $y=-2x-6$, the matching function is $f(x)=-2x-6$.

Step3: Match third standard function

For $y=\frac{4}{3}x-16$, the matching function is $f(x)=\frac{4}{3}x-16$.

Step4: Match fourth standard function

For $y=-\frac{1}{2}x-3$, the matching function is $f(x)=-\frac{1}{2}x-3$.

Answer:

1. $y=\frac{3}{4}x+12$ matches d. $f(x)=\frac{3}{4}x+12$
2. $y=-2x-6$ matches b. $f(x)=-2x-6$
3. $y=\frac{4}{3}x-16$ matches a. $f(x)=\frac{4}{3}x-16$
4. $y=-\frac{1}{2}x-3$ matches c. $f(x)=-\frac{1}{2}x-3$