Question

match the reaction on the right with the corresponding reaction on the left by writing the correct, matching number in the space provided. solid sodium + chlorine gas → solid sodium chloride solid sodium + liquid water → aqueous sodium hydroxide + hydrogen gas 2h₂(g) + o₂(g) → 2h₂o(l) 2h₂o₂(aq) → o₂(g) + 2h₂o(l) 1) aqueous hydrogen peroxide → oxygen gas + liquid water 2) 2na(s) + cl₂(g) → 2nacl(s) 3) hydrogen gas + oxygen gas → water gas 4) 2na(s) + 2h₂o(l) → 2naoh(aq) + h₂(g)

Explanation:

Step1: Analyze first reaction on left

Solid sodium reacting with chlorine gas to form solid sodium chloride is represented by the equation $2Na(s)+Cl_2(g)
ightarrow2NaCl(s)$. This matches with 2 on the right.

Step2: Analyze second reaction on left

Solid sodium reacting with liquid water to form aqueous sodium hydroxide and hydrogen gas is given by $2Na(s)+2H_2O(l)
ightarrow2NaOH(aq) + H_2(g)$. This matches with 4 on the right.

Step3: Analyze third reaction on left

The reaction $2H_2(g)+O_2(g)
ightarrow2H_2O(l)$ is hydrogen gas reacting with oxygen gas to form liquid water. This matches with 3 on the right (though the state of water is different in the description on right as water - gas but the reactants and products are the same conceptually).

Step4: Analyze fourth reaction on left

Aqueous hydrogen peroxide decomposing to oxygen gas and liquid water is represented by $2H_2O_2(aq)
ightarrow O_2(g)+2H_2O(l)$. This matches with 1 on the right.

Answer:

• Solid sodium + chlorine gas - solid sodium chloride: 2
• Solid sodium + liquid water - aqueous sodium hydroxide + hydrogen gas: 4
• $2H_2(g)+O_2(g)

ightarrow2H_2O(l)$: 3

• $2H_2O_2(aq)

ightarrow O_2(g)+2H_2O(l)$: 1