Question

1. $3x^2 + 4 = 166$

Explanation:

Step1: Subtract 4 from both sides

$3x^2 + 4 - 4 = 166 - 4$
$3x^2 = 162$

Step2: Divide both sides by 3

$\frac{3x^2}{3} = \frac{162}{3}$
$x^2 = 54$

Step3: Take square root of both sides

$x = \pm\sqrt{54}$
Simplify $\sqrt{54}$: $\sqrt{54}=\sqrt{9\times6}=3\sqrt{6}$
So $x = \pm 3\sqrt{6}$ or approximately $x\approx\pm7.35$ (if decimal form is needed)

Answer:

$x = 3\sqrt{6}$ or $x = -3\sqrt{6}$ (or $x\approx7.35$ or $x\approx -7.35$)