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Question
- $3x^{-2}y^{8} cdot 7x^{4}z^{-3}$
Step1: Multiply constant coefficients
$3 \times 7 = 21$
Step2: Combine $x$-terms via exponent addition
$x^{-2} \times x^{4} = x^{-2+4} = x^{2}$
Step3: Keep $y$-term (no like terms)
$y^{8}$
Step4: Keep $z$-term (no like terms)
$z^{-3} = \frac{1}{z^{3}}$
Step5: Combine all simplified terms
$21 \times x^{2} \times y^{8} \times \frac{1}{z^{3}}$
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$21x^{2}y^{8}z^{-3}$ or $\frac{21x^{2}y^{8}}{z^{3}}$