Question

1. $4x^2 - 5 = -1$

Explanation:

Step1: Isolate the $x^2$ term

Add 5 to both sides.
$4x^2 - 5 + 5 = -1 + 5$
$4x^2 = 4$

Step2: Solve for $x^2$

Divide both sides by 4.
$\frac{4x^2}{4} = \frac{4}{4}$
$x^2 = 1$

Step3: Find square roots of 1

Take square root of both sides.
$x = \pm\sqrt{1}$
$x = \pm1$

Answer:

$x = 1$ or $x = -1$