Question

1. $(-4a^{6}b^{4})^{2}$

Explanation:

Step1: Apply power to constant

$(-4)^2 = 16$

Step2: Apply power to $a^6$

$(a^6)^2 = a^{6\times2}=a^{12}$

Step3: Apply power to $b^4$

$(b^4)^2 = b^{4\times2}=b^{8}$

Step4: Multiply all results

$16 \times a^{12} \times b^{8}$

Answer:

$16a^{12}b^{8}$