Question

1. $\frac{2}{8}×2 =$
2. $3×\frac{1}{7} =$
3. $\frac{2}{3}×9 =$
4. $\frac{2}{10}×3 =$

Explanation:

Problem 3: $\boldsymbol{\frac{2}{8} \times 2}$

Step1: Simplify the fraction

Simplify $\frac{2}{8}$ to $\frac{1}{4}$.
$\frac{2}{8} = \frac{1}{4}$

Step2: Multiply by 2

Multiply $\frac{1}{4}$ by 2.
$\frac{1}{4} \times 2 = \frac{2}{4} = \frac{1}{2}$

Step1: Multiply the integer and numerator

Multiply 3 (which can be written as $\frac{3}{1}$) by $\frac{1}{7}$. Multiply the numerators: $3 \times 1 = 3$. The denominator remains 7.
$3 \times \frac{1}{7} = \frac{3 \times 1}{7} = \frac{3}{7}$

Step1: Rewrite 9 as a fraction

Rewrite 9 as $\frac{9}{1}$.
$9 = \frac{9}{1}$

Step2: Multiply the fractions

Multiply $\frac{2}{3}$ by $\frac{9}{1}$. Multiply the numerators: $2 \times 9 = 18$. Multiply the denominators: $3 \times 1 = 3$. Then simplify $\frac{18}{3}$.
$\frac{2}{3} \times \frac{9}{1} = \frac{18}{3} = 6$

Answer:

$\frac{1}{2}$

Problem 4: $\boldsymbol{3 \times \frac{1}{7}}$