Question

$(3x + \frac{1}{2}) + (4x + \frac{1}{4}) + (\frac{1}{2}x - 2)$

Explanation:

Step1: Remove parentheses

$3x + \frac{1}{2} + 4x + \frac{1}{4} + \frac{1}{2}x - 2$

Step2: Group like terms

$(3x + 4x + \frac{1}{2}x) + (\frac{1}{2} + \frac{1}{4} - 2)$

Step3: Combine x terms

$3x + 4x + \frac{1}{2}x = \frac{6}{2}x + \frac{8}{2}x + \frac{1}{2}x = \frac{15}{2}x$

Step4: Combine constant terms

$\frac{1}{2} + \frac{1}{4} - 2 = \frac{2}{4} + \frac{1}{4} - \frac{8}{4} = -\frac{5}{4}$

Answer:

$\frac{15}{2}x - \frac{5}{4}$