Question

1. (\frac{2}{3}y + 1=\frac{1}{6}y+8)

Explanation:

Step1: Move like - terms together

$\frac{2}{3}y-\frac{1}{6}y=8 - 1$

Step2: Find a common denominator for the y - terms

The common denominator of 3 and 6 is 6. So $\frac{2}{3}y=\frac{4}{6}y$. Then $\frac{4}{6}y-\frac{1}{6}y = 7$.

Step3: Combine the y - terms

$\frac{4y - 1y}{6}=7$, which simplifies to $\frac{3y}{6}=7$ or $\frac{y}{2}=7$.

Step4: Solve for y

Multiply both sides by 2: $y = 14$.

Answer:

$y = 14$