Question

(-4p + 3)^2

Explanation:

Step1: Apply square of sum formula

Recall $(a+b)^2=a^2+2ab+b^2$, let $a=-4p$, $b=3$.

Step2: Calculate each term

$(-4p)^2 = 16p^2$, $2\times(-4p)\times3=-24p$, $3^2=9$

Step3: Combine the terms

$16p^2 -24p +9$

Answer:

$16p^2 - 24p + 9$