Question

1. $h(n) = -n^2 + 3n$

$g(n) = 4n - 4$
find $(h + g)(6)$

Explanation:

Step1: Define $(h+g)(n)$

$(h+g)(n) = h(n) + g(n)$

Step2: Substitute the given functions

$(h+g)(n) = (-n^2 + 3n) + (4n - 4)$

Step3: Simplify the expression

$(h+g)(n) = -n^2 + 7n - 4$

Step4: Substitute $n=6$

$(h+g)(6) = -(6)^2 + 7(6) - 4$

Step5: Calculate the final value

$(h+g)(6) = -36 + 42 - 4$

Answer:

2