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$5sqrt3{4x + 3} = 15$ $x = \\boldsymbol{\\square}$

Question

$5sqrt3{4x + 3} = 15$
$x = \boldsymbol{\square}$

Explanation:

Step1: Isolate the cube root

Divide both sides by 5.
$$\sqrt[3]{4x+3} = \frac{15}{5} = 3$$

Step2: Eliminate the cube root

Cube both sides of the equation.
$$(\sqrt[3]{4x+3})^3 = 3^3$$
$$4x + 3 = 27$$

Step3: Isolate the term with $x$

Subtract 3 from both sides.
$$4x = 27 - 3 = 24$$

Step4: Solve for $x$

Divide both sides by 4.
$$x = \frac{24}{4} = 6$$

Answer:

6