Question

1. $2(x - 3)^2 = 8$

Explanation:

Step1: Divide both sides by 2

$\frac{2(x-3)^2}{2} = \frac{8}{2}$
Simplifies to: $(x-3)^2 = 4$

Step2: Take square root of both sides

$\sqrt{(x-3)^2} = \pm\sqrt{4}$
Simplifies to: $x-3 = \pm2$

Step3: Solve for x (case 1)

$x-3 = 2$
$x = 2 + 3$
$x = 5$

Step4: Solve for x (case 2)

$x-3 = -2$
$x = -2 + 3$
$x = 1$

Answer:

$x=1$ or $x=5$