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7. $3\frac{1}{4} + 4\frac{7}{8}$

Question

  1. $3\frac{1}{4} + 4\frac{7}{8}$

Explanation:

Step1: Convert mixed numbers to improper fractions or find a common denominator for the fractional parts. Let's find a common denominator for the fractions. The denominator of the first fraction is 4 and the second is 8, so the common denominator is 8. Convert \(3\frac{1}{4}\) to a fraction with denominator 8: \(3\frac{1}{4} = 3 + \frac{1\times2}{4\times2} = 3\frac{2}{8}\)

Step2: Now add the whole numbers and the fractional parts separately. The whole numbers are 3 and 4, and the fractional parts are \(\frac{2}{8}\) and \(\frac{7}{8}\). Add the whole numbers: \(3 + 4 = 7\). Add the fractional parts: \(\frac{2}{8} + \frac{7}{8} = \frac{9}{8}\)

Step3: Convert the improper fraction \(\frac{9}{8}\) to a mixed number and add it to the sum of the whole numbers. \(\frac{9}{8} = 1\frac{1}{8}\), so \(7 + 1\frac{1}{8} = 8\frac{1}{8}\)

Answer:

\(8\frac{1}{8}\)