Question

1. $\frac{u - 3v}{20u^{2}}+\frac{u + 3v}{20u^{2}}$

Explanation:

Step1: Combine numerators

Since the denominators are the same ($20u^{2}$), we add the numerators: $(u - 3v)+(u + 3v)$.
$(u - 3v)+(u + 3v)=u - 3v+u + 3v$

Step2: Simplify the numerator

Combine like - terms in the numerator: $u+u-3v + 3v=2u$.
So the fraction becomes $\frac{2u}{20u^{2}}$.

Step3: Simplify the fraction

Cancel out the common factors. Both 2 and 20 have a common factor of 2, and both $u$ and $u^{2}$ have a common factor of $u$.
$\frac{2u}{20u^{2}}=\frac{2\times u}{2\times10\times u\times u}=\frac{1}{10u}$ ($u
eq0$)

Answer:

$\frac{1}{10u}$ ($u
eq0$)