Question

1. $4a^{3}b^{2} \cdot 3a^{-4}b^{-3}$

Explanation:

Step1: Multiply coefficients

$4 \times 3 = 12$

Step2: Combine $a$ terms

$a^{3} \times a^{-4} = a^{3+(-4)} = a^{-1}$

Step3: Combine $b$ terms

$b^{2} \times b^{-3} = b^{2+(-3)} = b^{-1}$

Step4: Rewrite negative exponents

$a^{-1} = \frac{1}{a}$, $b^{-1} = \frac{1}{b}$; combine all parts
$12 \times \frac{1}{a} \times \frac{1}{b} = \frac{12}{ab}$

Answer:

$\frac{12}{ab}$