Question

factor $2n^2 - 8$:
a. $2(3n + 1)(3n - 1)$
b. $2(n + 4)^2$
c. $2(2n + 5)(2n - 5)$
d. $2(n + 2)(n - 2)$

Explanation:

Step1: Factor out common term

$2n^2 - 8 = 2(n^2 - 4)$

Step2: Apply difference of squares

$n^2 - 4 = (n+2)(n-2)$

Step3: Combine results

$2(n^2 - 4) = 2(n+2)(n-2)$

Answer:

d. $2(n+2)(n-2)$