Question

(\frac{27x^{3}y^{5}}{3x^{4}y^{2}})

Explanation:

Step1: Simplify constant coefficients

$\frac{27}{3} = 9$

Step2: Simplify $x$-terms (subtract exponents)

$\frac{x^3}{x^4} = x^{3-4} = x^{-1} = \frac{1}{x}$

Step3: Simplify $y$-terms (subtract exponents)

$\frac{y^5}{y^2} = y^{5-2} = y^3$

Step4: Combine all simplified parts

$9 \cdot \frac{1}{x} \cdot y^3$

Answer:

$\frac{9y^3}{x}$