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(\frac{3x}{x + 1} + \frac{3x}{2x + 2} =)

Question

(\frac{3x}{x + 1} + \frac{3x}{2x + 2} =)

Explanation:

Step1: Factor denominator of second term

Notice that $2x+2=2(x+1)$, so rewrite the expression:
$\frac{3x}{x+1} + \frac{3x}{2(x+1)}$

Step2: Find common denominator

The common denominator is $2(x+1)$. Adjust the first term:
$\frac{3x \times 2}{2(x+1)} + \frac{3x}{2(x+1)} = \frac{6x}{2(x+1)} + \frac{3x}{2(x+1)}$

Step3: Combine the fractions

Add the numerators over the common denominator:
$\frac{6x + 3x}{2(x+1)} = \frac{9x}{2(x+1)}$

Answer:

$\frac{9x}{2(x+1)}$