Question

\frac{5}{11} 〇 1
\frac{13}{9} 〇 \frac{5}{9}
\frac{8}{8} 〇 1

Explanation:

Step1: Analyze \(\frac{5}{11}\) and \(1\)

We know that \(1=\frac{11}{11}\). When comparing two fractions with the same denominator, the fraction with the larger numerator is larger. Since \(5 < 11\), we have \(\frac{5}{11}<\frac{11}{11}\), so \(\frac{5}{11}< 1\).

Step2: Analyze \(\frac{13}{9}\) and \(\frac{5}{9}\)

For two fractions with the same denominator (in this case, the denominator is \(9\)), we compare the numerators. Since \(13>5\), by the rule of comparing fractions with the same denominator, \(\frac{13}{9}>\frac{5}{9}\).

Step3: Analyze \(\frac{8}{8}\) and \(1\)

We know that \(\frac{8}{8} = 1\) because a fraction with the same numerator and denominator is equal to \(1\). But looking at the symbol in the image, it seems there might be a typo or mis - display, but if we consider the fraction \(\frac{8}{8}\), it is equal to \(1\). However, if we assume the intended fraction was less than \(1\) (maybe a different numerator), but based on the given \(\frac{8}{8}\), \(\frac{8}{8}=1\). But from the image, the symbol is \(<\), which might be an error. But following the fraction \(\frac{8}{8}\), it should be equal to \(1\). But if we take the first two comparisons:

For \(\frac{5}{11}\) and \(1\): \(\frac{5}{11}<1\)

For \(\frac{13}{9}\) and \(\frac{5}{9}\): \(\frac{13}{9}>\frac{5}{9}\)

For \(\frac{8}{8}\) and \(1\): \(\frac{8}{8} = 1\) (but the symbol in the image is \(<\), which is incorrect for \(\frac{8}{8}\) and \(1\))

Answer:

• \(\frac{5}{11}\) \(\boldsymbol{<}\) \(1\)
• \(\frac{13}{9}\) \(\boldsymbol{>}\) \(\frac{5}{9}\)
• \(\frac{8}{8}\) \(\boldsymbol{=}\) \(1\) (Note: The symbol \(<\) in the image for \(\frac{8}{8}\) and \(1\) is incorrect as \(\frac{8}{8}=1\))