Question

$\frac{-8x^{5}+28x^{4}-4x^{3}}{4x^{3}}$

Explanation:

Step1: Split the fraction

$\frac{-8x^5 + 28x^4 - 4x^3}{4x^3} = \frac{-8x^5}{4x^3} + \frac{28x^4}{4x^3} - \frac{4x^3}{4x^3}$

Step2: Simplify each term

$\frac{-8x^5}{4x^3} = -2x^{5-3} = -2x^2$; $\frac{28x^4}{4x^3} = 7x^{4-3} = 7x$; $\frac{4x^3}{4x^3} = 1$

Answer:

$-2x^2 + 7x - 1$