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operation. $(8x^2 - 7x + 8) - (4x^2 - 3x + 3)$

Question

operation.
$(8x^2 - 7x + 8) - (4x^2 - 3x + 3)$

Explanation:

Step1: Remove parentheses

To remove the parentheses, we distribute the negative sign to the terms inside the second parentheses:
$$(8x^2 - 7x + 8) - (4x^2 - 3x + 3)=8x^2 - 7x + 8 - 4x^2 + 3x - 3$$

Step2: Combine like terms

  • For the \(x^2\) terms: \(8x^2-4x^2 = 4x^2\)
  • For the \(x\) terms: \(-7x + 3x=-4x\)
  • For the constant terms: \(8 - 3 = 5\)

Combining these results, we get:
$$4x^2-4x + 5$$

Answer:

\(4x^2-4x + 5\)