Question

simplify: $\frac{3x^{5}y}{12x^{3}y^{2}}$○ $\frac{4}{x^{2}y}$○ $4x^{2}y$○ $\frac{x^{2}y}{4}$○ $\frac{x^{2}}{4y}$

Explanation:

Step1: Simplify the coefficients

$\frac{3}{12} = \frac{1}{4}$

Step2: Simplify $x$-terms

$\frac{x^5}{x^3} = x^{5-3} = x^2$

Step3: Simplify $y$-terms

$\frac{y}{y^2} = y^{1-2} = y^{-1} = \frac{1}{y}$

Step4: Combine all simplified parts

$\frac{1}{4} \times x^2 \times \frac{1}{y} = \frac{x^2}{4y}$

Answer:

$\boldsymbol{\frac{x^2}{4y}}$ (corresponding to the fourth option)