Question

simplify.
\sqrt{3} \cdot \sqrt{2}

Explanation:

Step1: Apply square root product rule

Recall that $\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$ for non-negative $a,b$.
$\sqrt{3} \cdot \sqrt{2} = \sqrt{3 \times 2}$

Step2: Multiply the radicands

Calculate the product inside the square root.
$\sqrt{3 \times 2} = \sqrt{6}$

Answer:

$\sqrt{6}$