Question

solve $a = 2\pi r^2 + 2\pi rh$ for $h$.
\bigcirc a. $h = a - 2\pi r^2 - 2\pi r$
\bigcirc b. $h = a - r$
\bigcirc c. $h = \frac{2\pi r^2 - a}{2\pi r}$
\bigcirc d. $h = \frac{2\pi r}{a - 2\pi r^2}$
\bigcirc e. $h = \frac{a - 2\pi r^2}{2\pi r}$

Explanation:

Step1: Isolate the term with h

Start with the equation \( A = 2\pi r^2 + 2\pi r h \). Subtract \( 2\pi r^2 \) from both sides to get \( A - 2\pi r^2 = 2\pi r h \).

Step2: Solve for h

Divide both sides of the equation \( A - 2\pi r^2 = 2\pi r h \) by \( 2\pi r \) to isolate \( h \). This gives \( h=\frac{A - 2\pi r^2}{2\pi r} \).

Answer:

E. \( h = \frac{A - 2\pi r^2}{2\pi r} \)