Question

solve for h.
\\(\frac{h}{6} - 1 = -3\\)
\\(h = \square\\)

Explanation:

Step1: Add 1 to both sides

To isolate the term with \( h \), we add 1 to both sides of the equation \(\frac{h}{6}-1 = -3\). This gives us \(\frac{h}{6}-1 + 1=-3 + 1\), which simplifies to \(\frac{h}{6}=-2\).

Step2: Multiply both sides by 6

To solve for \( h \), we multiply both sides of the equation \(\frac{h}{6}=-2\) by 6. So, \(6\times\frac{h}{6}=6\times(-2)\), which simplifies to \(h = - 12\).

Answer:

\(h=-12\)