solve for x.\ $2x^2 - 12x + 18 = 0$\ $x = \\square$

$solve for x.\ $2x^2 - 12x + 18 = 0$\ $x = \\square$$

solve for x.\
$2x^2 - 12x + 18 = 0$\
$x = \square$

Divide each term of the equation $2x^{2}-12x + 18 = 0$ by 2. We get $x^{2}-6x + 9 = 0$.

Notice that $x^{2}-6x + 9$ is a perfect square trinomial, which can be factored as $(x - 3)^{2}=0$.

Take the square root of both sides: $x - 3 = 0$, so $x = 3$.

$x = 3$