QUESTION IMAGE
Question
solve for x. $x^2 + 2x - 48 = 0$ $x = 0$ $x = 6$ $x = 6$ or $x = -8$ $x = -6$ or $x = 8$
Step1: Factor the quadratic equation
We need two numbers that multiply to $-48$ and add to $2$. These numbers are $8$ and $-6$.
$x^2 + 2x - 48 = (x + 8)(x - 6) = 0$
Step2: Set each factor equal to 0
For a product of factors to be 0, at least one factor must be 0.
$x + 8 = 0$ or $x - 6 = 0$
Step3: Solve for x in each equation
Solve $x + 8 = 0$: $x = -8$
Solve $x - 6 = 0$: $x = 6$
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$x = 6$ or $x = -8$