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solve $log_{2}(3x - 13) = 3$. $x = \\square$

Question

solve $log_{2}(3x - 13) = 3$.
$x = \square$

Explanation:

Step1: Convert log to exponential form

Recall $\log_b(a)=c \iff b^c=a$. So:
$$2^3 = 3x - 13$$

Step2: Calculate $2^3$

Compute the left-hand side:
$$8 = 3x - 13$$

Step3: Isolate the term with $x$

Add 13 to both sides:
$$8 + 13 = 3x$$
$$21 = 3x$$

Step4: Solve for $x$

Divide both sides by 3:
$$x = \frac{21}{3}$$

Answer:

$7$