Question

$x^2 = 100$; $x^2 = 121$; $4x^2 = 64$

Explanation:

Step1: Solve $x^2=100$

Take square root of both sides:
$x = \pm\sqrt{100} = \pm10$

Step2: Solve $x^2=121$

Take square root of both sides:
$x = \pm\sqrt{121} = \pm11$

Step3: Solve $4x^2=64$

First divide both sides by 4:
$x^2 = \frac{64}{4} = 16$
Take square root of both sides:
$x = \pm\sqrt{16} = \pm4$

Answer:

For $x^2=100$: $x=10$ or $x=-10$
For $x^2=121$: $x=11$ or $x=-11$
For $4x^2=64$: $x=4$ or $x=-4$