Question

the measured mass and volume of three metal samples are shown. rank the samples according to their density. sample a: mass 65.3 g, volume 10.0 ml; sample b: mass 72.1 g, volume 10.0 ml; sample c: mass 88.9 g, volume 10.0 ml

Explanation:

Step1: Recall density formula

Density $
ho=\frac{m}{V}$, where $m$ is mass and $V$ is volume.

Step2: Calculate density of Sample A

Given $m_A = 65.3\ g$ and $V_A=10.0\ mL$, then $
ho_A=\frac{65.3\ g}{10.0\ mL}=6.53\ g/mL$.

Step3: Calculate density of Sample B

Given $m_B = 72.1\ g$ and $V_B = 10.0\ mL$, then $
ho_B=\frac{72.1\ g}{10.0\ mL}=7.21\ g/mL$.

Step4: Calculate density of Sample C

Given $m_C = 88.9\ g$ and $V_C=10.0\ mL$, then $
ho_C=\frac{88.9\ g}{10.0\ mL}=8.89\ g/mL$.

Step5: Rank the samples

Since $6.53\ g/mL<7.21\ g/mL < 8.89\ g/mL$, the ranking from least - dense to most - dense is Sample A, Sample B, Sample C.

Answer:

1. Sample A
2. Sample B
3. Sample C