Question

ments
d contain only positive exponents.

1. $2nn^{-3}$

Explanation:

Step1: Combine like terms

When multiplying terms with the same base, add exponents: $n \times n^{-3} = n^{1 + (-3)} = n^{-2}$
So $2nn^{-3} = 2n^{-2}$

Step2: Rewrite with positive exponents

A term with a negative exponent $a^{-k} = \frac{1}{a^k}$, so $n^{-2} = \frac{1}{n^2}$
Substitute back: $2n^{-2} = 2 \times \frac{1}{n^2}$

Answer:

$\frac{2}{n^2}$