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metric ↔ imperial 1 in. ≈ 2.54 cm 1 ft. ≈ 30.48 cm 1 yd. ≈ 0.9144 m 1 m…

Question

metric ↔ imperial
1 in. ≈ 2.54 cm
1 ft. ≈ 30.48 cm
1 yd. ≈ 0.9144 m
1 mi. ≈ 1.609 km
shaquille o’neal is 7 feet 1 inch tall. what is his height in centimeters?
nathan has a piece of string that is 30 feet long and needs a piece of string that is 10 m long. does he have enough string? explain with words and calculations.
the trip from dayton columbus is about 121 km. if jack makes a round trip, what is the distance in miles? round to the nearest mile.
sarah has bought a macramé rope that is 2 ft. 5 in. long. she trims off 12 cm of it to hang a plant in her room. how long is the trimmed macramé rope in cm?

Explanation:

Response
First Question: Shaquille O'Neal's Height in Centimeters

Step1: Convert feet to centimeters

Shaquille O'Neal is 7 feet tall. Using the conversion factor \(1\ \text{ft} \approx 30.48\ \text{cm}\), we calculate the height from feet: \(7 \times 30.48 = 213.36\ \text{cm}\)

Step2: Convert inch to centimeters

He is also 1 inch tall. Using the conversion factor \(1\ \text{in} \approx 2.54\ \text{cm}\), we calculate the height from inches: \(1 \times 2.54 = 2.54\ \text{cm}\)

Step3: Sum the two heights

Add the height from feet and the height from inches: \(213.36 + 2.54 = 215.9\ \text{cm}\)

Step1: Convert feet to centimeters

Nathan's string is 30 feet long. Using \(1\ \text{ft} \approx 30.48\ \text{cm}\), we get: \(30 \times 30.48 = 914.4\ \text{cm}\)

Step2: Convert centimeters to meters

Since \(1\ \text{m} = 100\ \text{cm}\), we convert the length to meters: \(\frac{914.4}{100} = 9.144\ \text{m}\)

Step3: Compare with required length

Nathan needs 10 m of string. Since \(9.144 < 10\), he does not have enough string.

Step1: Calculate the round - trip distance in kilometers

The one - way trip is 121 km, so the round - trip distance is \(121\times2 = 242\ \text{km}\)

Step2: Convert kilometers to miles

Using the conversion factor \(1\ \text{mi} \approx 1.609\ \text{km}\), we calculate the distance in miles: \(\frac{242}{1.609}\approx150.39\), which rounds to 150 miles.

Answer:

\(215.9\ \text{cm}\)

Second Question: Nathan's String Length