QUESTION IMAGE
Question
micah richard
advanced math
homework 6
- $-7(m - 9) - 2m = 12$
- $16 = 9 - 4(2r + 7) - 1$
- $-8(4n - 1) = 2(9 - 3n)$
- $-\frac{4}{3}(12v - 18 + 32) = -8(7 + 2v)$
- $1 = \frac{x\cdot 2\pi r}{800}$ solve for $r$
- $\frac{3y - x}{3 - 2x} = -9$ solve for $y$
Problem 1: Solve for $m$
Step1: Expand the parentheses
$-7(m-9) - 2m = 12$
$-7m + 63 - 2m = 12$
Step2: Combine like terms
$-9m + 63 = 12$
Step3: Isolate the variable term
$-9m = 12 - 63$
$-9m = -51$
Step4: Solve for $m$
$m = \frac{-51}{-9} = \frac{17}{3}$
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Problem 3: Solve for $r$
Step1: Simplify constants on right
$16 = 9 - 4(2r+7) - 1$
$16 = 8 - 4(2r+7)$
Step2: Expand the parentheses
$16 = 8 - 8r - 28$
Step3: Combine like terms
$16 = -20 - 8r$
Step4: Isolate the variable term
$8r = -20 - 16$
$8r = -36$
Step5: Solve for $r$
$r = \frac{-36}{8} = -\frac{9}{2}$
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Problem 5: Solve for $n$
Step1: Expand both sides
$-8(4n-1) = 2(9-3n)$
$-32n + 8 = 18 - 6n$
Step2: Isolate variable terms
$-32n + 6n = 18 - 8$
$-26n = 10$
Step3: Solve for $n$
$n = \frac{10}{-26} = -\frac{5}{13}$
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Problem 7: Solve for $v$
Step1: Simplify inside left parentheses
$-\frac{4}{3}(12v - 18 + 32) = -8(7+2v)$
$-\frac{4}{3}(12v + 14) = -8(7+2v)$
Step2: Expand both sides
$-\frac{4}{3}(12v) - \frac{4}{3}(14) = -56 - 16v$
$-16v - \frac{56}{3} = -56 - 16v$
Step3: Analyze the equation
Add $16v$ to both sides:
$-\frac{56}{3} = -56$
This is a false statement, so there is no solution.
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Problem 9: Solve for $r$
Step1: Multiply both sides by 360
$1 = \frac{x \cdot 2 \pi r}{360}$
$360 = 2 \pi x r$
Step2: Isolate $r$
$r = \frac{360}{2 \pi x} = \frac{180}{\pi x}$
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Problem 11: Solve for $y$
Step1: Multiply both sides by denominator
$\frac{3y - x}{3-2x} = 4$
$3y - x = 4(3-2x)$
Step2: Expand the right side
$3y - x = 12 - 8x$
Step3: Isolate the $y$ term
$3y = 12 - 8x + x$
$3y = 12 - 7x$
Step4: Solve for $y$
$y = \frac{12 - 7x}{3}$
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- $m = \frac{17}{3}$
- $r = -\frac{9}{2}$
- $n = -\frac{5}{13}$
- No solution
- $r = \frac{180}{\pi x}$
- $y = \frac{12 - 7x}{3}$