Question

mixed practice!
name the following:
na2o
caco3
pbs2
sn3n2
cu3po4
hgf2

Explanation:

For $\boldsymbol{\ce{Na2O}}$:

Step1: Identify cation and anion

Cation: $\ce{Na+}$ (sodium ion), Anion: $\ce{O^{2-}}$ (oxide ion).

Step2: Name using ionic naming rules

Name the cation first, then the anion. The subscripts indicate the ratio (2 $\ce{Na+}$ to balance 1 $\ce{O^{2-}}$). So it's sodium oxide.

For $\boldsymbol{\ce{CaCO3}}$:

Step1: Identify cation and polyatomic anion

Cation: $\ce{Ca^{2+}}$ (calcium ion), Anion: $\ce{CO3^{2-}}$ (carbonate ion).

Step2: Name using ionic naming rules

Name cation then polyatomic anion. So it's calcium carbonate.

For $\boldsymbol{\ce{PbS2}}$:

Step1: Identify cation and anion

Cation: $\ce{Pb^{4+}}$ (lead(IV) ion, since 2 $\ce{S^{2-}}$ need 4+ from Pb: $x + 2\times(-2)=0\Rightarrow x = +4$), Anion: $\ce{S^{2-}}$ (sulfide ion).

Step2: Name using ionic naming rules (with Roman numeral for Pb's charge)

Lead(IV) sulfide.

For $\boldsymbol{\ce{Sn3N2}}$:

Answer:

s:

• $\ce{Na2O}$: Sodium Oxide
• $\ce{CaCO3}$: Calcium Carbonate
• $\ce{PbS2}$: Lead(IV) Sulfide
• $\ce{Sn3N2}$: Tin(II) Nitride
• $\ce{Cu3PO4}$: Copper(I) Phosphate
• $\ce{HgF2}$: Mercury(II) Fluoride