Question

modeling real life the temperature of dry ice is $-109.3^{circ}\text{f}$. this is $184.9^{circ}\text{f}$ less than the outside temperature. solve an equation to find the outside temperature $t$ (in degrees fahrenheit).

an equation is $-109.3 = \square$

the outside temperature is $\square^{circ}\text{f}$.

Explanation:

Step1: Define the equation

The dry ice temperature ($-109.3^\circ F$) is $184.9^\circ F$ less than the outside temperature \( t \). So the equation is \( -109.3 = t - 184.9 \).

Step2: Solve for \( t \)

To find \( t \), we add \( 184.9 \) to both sides of the equation:
\( t = -109.3 + 184.9 \)
\( t = 75.6 \)

Answer:

An equation is \( -109.3 = t - 184.9 \)
The outside temperature is \( 75.6^\circ F \)