molar conversion practice
1 mole of sodium atoms = ______ atoms
nole of co₂ molecules = ______ molecules
the average atomic mass listed on the pt equals ____ mole which equals ______ atoms.
1.01g of hydrogen is equal to ____ mole of hydrogen which is ______ atoms of hydrogen.
moles and atoms and ions... oh my!!!
1. in 1 molecule of h₂o: how many hydrogen atoms?
how many oxygen atoms?
in 1 mole of h₂o molecules: how many moles of hydrogen atoms?
how many moles of oxygen atoms?
how many moles of total atoms?
2. in 1 formula unit of nacl: how many sodium ions?
how many chloride ions?
in 1 mole of nacl formula units: how many moles of sodium ions?
how many moles of chloride ions?
how many moles of total ions?
3. in 1 mole of alcl₃: how many moles of aluminum ions?
how many moles of chloride ions?
how many moles of total ions?
4. in 1 mole of al₂(co₃)₃: how many moles of aluminum ions?
how many moles of carbonate ions?
how many moles of total ions?
how many moles of total atoms?
molar conversions:
1. how many atoms are in 3.0 moles of argon gas?
2. in 27.0 grams of lithium, how many atoms are there?

Question

Accepted Answer

### 1. Molar Conversion Practice (First part)
#### 1 mole of sodium atoms = ______ atoms
# Explanation:
## Step1: Recall Avogadro's number
Avogadro's number is $ 6.022 \times 10^{23} $ particles per mole. For sodium atoms, 1 mole of any substance contains $ 6.022 \times 10^{23} $ particles (atoms, molecules, etc.).
So, 1 mole of sodium atoms = $ 6.022 \times 10^{23} $ atoms.

#### 1 mole of $ CO_2 $ molecules = ______ molecules
## Step1: Apply Avogadro's number
1 mole of any molecular substance contains $ 6.022 \times 10^{23} $ molecules. So, 1 mole of $ CO_2 $ molecules = $ 6.022 \times 10^{23} $ molecules.

#### The average atomic mass listed on the PT equals ____ mole which equals ______ atoms.
## Step1: Understand molar mass and Avogadro's number
The average atomic mass (in grams per mole) of an element is equal to 1 mole of that element, and 1 mole contains $ 6.022 \times 10^{23} $ atoms. So, the average atomic mass (in g/mol) equals 1 mole which equals $ 6.022 \times 10^{23} $ atoms.

#### 1.01g of Hydrogen is equal to ____ mole of Hydrogen which is ______ atoms of hydrogen.
## Step1: Calculate moles of Hydrogen
The molar mass of Hydrogen ($ H_2 $) is approximately 2.02 g/mol, but for atomic hydrogen (H), molar mass is approximately 1.01 g/mol. Using the formula $ n=\frac{m}{M} $, where $ m = 1.01 $ g and $ M = 1.01 $ g/mol.
$ n=\frac{1.01\ \text{g}}{1.01\ \text{g/mol}} = 1\ \text{mole} $
## Step2: Calculate number of atoms
Using Avogadro's number, number of atoms $ = n\times N_A = 1\ \text{mole} \times 6.022 \times 10^{23}\ \text{atoms/mol} = 6.022 \times 10^{23}\ \text{atoms} $
So, 1.01g of Hydrogen is equal to 1 mole of Hydrogen which is $ 6.022 \times 10^{23} $ atoms of hydrogen.

### 2. Moles and Atoms and Ions... OH MY!!!
#### 1. In 1 molecule of $ H_2O $:
- How many hydrogen atoms?
  In one $ H_2O $ molecule, the subscript of H is 2, so there are 2 hydrogen atoms.
- How many oxygen atoms?
  The subscript of O is 1, so there is 1 oxygen atom.

In 1 mole of $ H_2O $ molecules:
- How many moles of hydrogen atoms?
  From the formula $ H_2O $, each mole of $ H_2O $ has 2 moles of H atoms (since 1 mole of $ H_2O $ has 2 moles of H, as per the ratio 2:1:1 for H:O:molecule).
- How many moles of oxygen atoms?
  Each mole of $ H_2O $ has 1 mole of O atoms.
- How many moles of total atoms?
  Moles of H + Moles of O = $ 2 + 1 = 3 $ moles of total atoms.

#### 2. In 1 formula unit of $ NaCl $:
- How many sodium ions?
  In one $ NaCl $ formula unit, there is 1 $ Na^+ $ ion.
- How many chloride ions?
  In one $ NaCl $ formula unit, there is 1 $ Cl^- $ ion.

In 1 mole of $ NaCl $ formula units:
- How many moles of sodium ions?
  1 mole of $ NaCl $ formula units contains 1 mole of $ Na^+ $ ions (1:1 ratio of $ NaCl $ to $ Na^+ $).
- How many moles of chloride ions?
  1 mole of $ NaCl $ formula units contains 1 mole of $ Cl^- $ ions (1:1 ratio of $ NaCl $ to $ Cl^- $).
- How many moles of total ions?
  Moles of $ Na^+ $ + Moles of $ Cl^- $ = $ 1 + 1 = 2 $ moles of total ions.

#### 3. In 1 mole of $ AlCl_3 $:
- How many moles of aluminum ions?
  In $ AlCl_3 $, the ratio of $ Al^{3+} $ to $ AlCl_3 $ is 1:1. So, 1 mole of $ AlCl_3 $ contains 1 mole of $ Al^{3+} $ ions.
- How many moles of chloride ions?
  The ratio of $ Cl^- $ to $ AlCl_3 $ is 3:1. So, 1 mole of $ AlCl_3 $ contains $ 3 $ moles of $ Cl^- $ ions.
- How many moles of total ions?
  Moles of $ Al^{3+} $ + Moles of $ Cl^- $ = $ 1 + 3 = 4 $ moles of total ions.

#### 4. In 1 mole of $ Al_2(CO_3)_3 $:
- How many moles of aluminum ions?
  In $ Al_2(CO_3)_3 $, the subscript of $ Al^{3+} $ is 2, so 1 mole of $ Al_2(CO_3)_3 $ contains 2 moles of $ Al^{3+} $ ions.
- How many moles of carbonate ions?
  The subscript of $ CO_3^{2-} $ is 3, so 1 mole of $ Al_2(CO_3)_3 $ contains 3 moles of $ CO_3^{2-} $ ions.
- How many moles of total ions?
  Moles of $ Al^{3+} $ + Moles of $ CO_3^{2-} $ = $ 2 + 3 = 5 $ moles of total ions.
- How many moles of total atoms?
  First, find atoms in one $ Al_2(CO_3)_3 $ formula:
  - Al: 2 atoms
  - C: $ 3 \times 1 = 3 $ atoms (3 carbonate ions, each with 1 C)
  - O: $ 3 \times 3 = 9 $ atoms (3 carbonate ions, each with 3 O)
  Total atoms per formula: $ 2 + 3 + 9 = 14 $ atoms.
  So, 1 mole of $ Al_2(CO_3)_3 $ contains 14 moles of total atoms (since 1 mole of the compound has 14 moles of atoms, as per the formula's atom count).

### 3. Molar Conversions:
#### 1. How many atoms are in 3.0 moles of Argon gas?
# Explanation:
## Step1: Recall Avogadro's number
Argon is a monatomic gas, so 1 mole of Ar contains $ 6.022 \times 10^{23} $ atoms.
## Step2: Calculate number of atoms
Number of atoms $ = n \times N_A $, where $ n = 3.0 $ moles and $ N_A = 6.022 \times 10^{23}\ \text{atoms/mol} $.
$ \text{Number of atoms} = 3.0\ \text{moles} \times 6.022 \times 10^{23}\ \text{atoms/mol} = 1.8066 \times 10^{24}\ \text{atoms} $ (approx $ 1.8 \times 10^{24} $ atoms)
# Answer: $ 1.8 \times 10^{24} $ atoms (or $ 1.8066 \times 10^{24} $ atoms)

#### 2. In 27.0 grams of lithium, how many atoms are there?
# Explanation:
## Step1: Calculate moles of Lithium
Molar mass of Li is approximately 6.94 g/mol. Using $ n = \frac{m}{M} $, where $ m = 27.0 $ g and $ M = 6.94 $ g/mol.
$ n = \frac{27.0\ \text{g}}{6.94\ \text{g/mol}} \approx 3.89\ \text{moles} $
## Step2: Calculate number of atoms
Using Avogadro's number, number of atoms $ = n \times N_A = 3.89\ \text{moles} \times 6.022 \times 10^{23}\ \text{atoms/mol} \approx 2.34 \times 10^{24}\ \text{atoms} $
# Answer: Approximately $ 2.34 \times 10^{24} $ atoms (or more precisely, $ \frac{27.0}{6.94} \times 6.022 \times 10^{23} \approx 2.34 \times 10^{24} $ atoms)

### Final Answers (Summarized for each part):
- 1 mole of sodium atoms: $ \boldsymbol{6.022 \times 10^{23}} $ atoms
- 1 mole of $ CO_2 $ molecules: $ \boldsymbol{6.022 \times 10^{23}} $ molecules
- Average atomic mass (PT) = 1 mole = $ \boldsymbol{6.022 \times 10^{23}} $ atoms
- 1.01g H: 1 mole, $ \boldsymbol{6.022 \times 10^{23}} $ atoms

#### Moles and Atoms and Ions:
1. $ H_2O $:
   - 1 molecule: 2 H atoms, 1 O atom
   - 1 mole $ H_2O $: 2 moles H, 1 mole O, 3 moles total atoms

2. $ NaCl $:
   - 1 formula unit: 1 $ Na^+ $, 1 $ Cl^- $
   - 1 mole $ NaCl $: 1 mole $ Na^+ $, 1 mole $ Cl^- $, 2 moles total ions

3. $ AlCl_3 $:
   - 1 mole: 1 mole $ Al^{3+} $, 3 moles $ Cl^- $, 4 moles total ions

4. $ Al_2(CO_3)_3 $:
   - 1 mole: 2 moles $ Al^{3+} $, 3 moles $ CO_3^{2-} $, 5 moles total ions, 14 moles total atoms

#### Molar Conversions:
1. 3.0 moles Ar: $ \boldsymbol{1.8 \times 10^{24}} $ atoms (or $ 1.8066 \times 10^{24} $)
2. 27.0g Li: Approximately $ \boldsymbol{2.34 \times 10^{24}} $ atoms

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

1. Molar Conversion Practice (First part)

1 mole of sodium atoms = ______ atoms

Step1: Recall Avogadro's number

1 mole of \( CO_2 \) molecules = ______ molecules

Step1: Apply Avogadro's number

The average atomic mass listed on the PT equals mole which equals __ atoms.

Step1: Understand molar mass and Avogadro's number

1.01g of Hydrogen is equal to mole of Hydrogen which is __ atoms of hydrogen.

Step1: Calculate moles of Hydrogen

Step2: Calculate number of atoms

2. Moles and Atoms and Ions... OH MY!!!

1. In 1 molecule of \( H_2O \):

2. In 1 formula unit of \( NaCl \):

3. In 1 mole of \( AlCl_3 \):

4. In 1 mole of \( Al_2(CO_3)_3 \):

Step1: Recall Avogadro's number

Step2: Calculate number of atoms

Step1: Calculate moles of Lithium

Step2: Calculate number of atoms

Answer:

2. In 27.0 grams of lithium, how many atoms are there?

QUESTION IMAGE

Question

Explanation:

1. Molar Conversion Practice (First part)

1 mole of sodium atoms = ______ atoms

Step1: Recall Avogadro's number

1 mole of \( CO_2 \) molecules = ______ molecules

Step1: Apply Avogadro's number

The average atomic mass listed on the PT equals __ mole which equals ____ atoms.

Step1: Understand molar mass and Avogadro's number

1.01g of Hydrogen is equal to __ mole of Hydrogen which is ____ atoms of hydrogen.

Step1: Calculate moles of Hydrogen

Step2: Calculate number of atoms

2. Moles and Atoms and Ions... OH MY!!!

1. In 1 molecule of \( H_2O \):

2. In 1 formula unit of \( NaCl \):

3. In 1 mole of \( AlCl_3 \):

4. In 1 mole of \( Al_2(CO_3)_3 \):

Step1: Recall Avogadro's number

Step2: Calculate number of atoms

Step1: Calculate moles of Lithium

Step2: Calculate number of atoms

Answer:

2. In 27.0 grams of lithium, how many atoms are there?

The average atomic mass listed on the PT equals mole which equals __ atoms.

1.01g of Hydrogen is equal to mole of Hydrogen which is __ atoms of hydrogen.