Question

mookie has a solution of ph 6 and keebo has a solution of ph 3. keebo said his solution has “double the concentration of compared to mookie’s solution.” do you agree? explain your thinking? (4pts)

Explanation:

Step1: Recall pH formula

The formula for pH is $pH = -\log[H^+]$, where $[H^+]$ is the hydrogen - ion concentration.

Step2: Calculate $[H^+]$ for Mookie's solution

For Mookie's solution with $pH = 6$, we have $6=-\log[H^+_1]$. Then $[H^+_1]=10^{-6}\ M$ (since $-\log[H^+]=pH$ implies $[H^+]=10^{-pH}$).

Step3: Calculate $[H^+]$ for Keebo's solution

For Keebo's solution with $pH = 3$, we have $3 = -\log[H^+_2]$. Then $[H^+_2]=10^{-3}\ M$.

Step4: Compare the concentrations

Calculate the ratio $\frac{[H^+_2]}{[H^+_1]}=\frac{10^{-3}}{10^{-6}} = 10^{(- 3-( - 6))}=10^{3}=1000$. So Keebo's solution has 1000 times the concentration of Mookie's solution, not double.

Answer:

No, Keebo is wrong. Keebo's solution has 1000 times the hydrogen - ion concentration of Mookie's solution, not double, as calculated from the pH formula $pH = -\log[H^+]$.