Question

mr. franklin needs to draw a perfect circle. the endpoints of one of the diameters needs to fall on (7, 1) and (-1, -1). where should he locate the center of the circle?

Explanation:

Step1: Find x-coordinate of center

The x-coordinate of the center is the average of the x-coordinates of the diameter endpoints.
$\text{Center } x = \frac{7 + (-1)}{2} = \frac{6}{2} = 3$

Step2: Find y-coordinate of center

The y-coordinate of the center is the average of the y-coordinates of the diameter endpoints.
$\text{Center } y = \frac{1 + (-1)}{2} = \frac{0}{2} = 0$

Answer:

The center of the circle should be located at $(3, 0)$