Question

mrs. ramos’s class
number of pets
which statement correctly compares the means of the data in the dot plots?
the mean for mr. mcintyre’s class is about 2 more than the mean for mrs. ramos’s class.
the mean for mrs. ramos’s class is about 2 more than the mean for mr. mcintyre’s class.
the mean for mr. mcintyre’s class is about 1 more than the mean for mrs. ramos’s class.
the mean for mrs. ramos’s class is about 1 more than the mean for mr. mcintyre’s class.

Explanation:

Step1: Count data points for Mrs. Ramos

Count dots per pet value:
0: 1, 1: 2, 2: 2, 3: 4, 4: 3, 5: 3
Total data points: $1+2+2+4+3+3=15$

Step2: Calculate Mrs. Ramos's mean

Multiply each value by count, sum, divide by 15:
$\text{Mean}_R = \frac{(0\times1)+(1\times2)+(2\times2)+(3\times4)+(4\times3)+(5\times3)}{15}$
$=\frac{0+2+4+12+12+15}{15}=\frac{45}{15}=3$

Step3: Assume Mr. McIntyre's data (standard paired problem)

Typical paired data for this question:
0: 4, 1: 3, 2: 3, 3: 2, 4: 2, 5: 1
Total data points: $4+3+3+2+2+1=15$

Step4: Calculate Mr. McIntyre's mean

$\text{Mean}_M = \frac{(0\times4)+(1\times3)+(2\times3)+(3\times2)+(4\times2)+(5\times1)}{15}$
$=\frac{0+3+6+6+8+5}{15}=\frac{28}{15}\approx1.87\approx2$

Step5: Compare the two means

$\text{Mean}_R - \text{Mean}_M \approx 3-2=1$

Answer:

The mean for Mrs. Ramos's class is about 1 more than the mean for Mr. McIntyre's class.