QUESTION IMAGE
Question
multiple choice 10 points
an unknown compound is found to have the following stable isotopes:
| isotope | atomic mass (amu) | percent abundance (%) |
|---|---|---|
| 2 | 15.909 | 9.86 |
| 3 | 16.909 | 7.00 |
| 4 | 17.500 | 82.58 |
determine the weighted average atomic mass for this compound.
16.91
17.28
16.06
17.55
Step1: Convert percentages to decimals
$0.56\% = 0.0056$, $9.86\%=0.0986$, $7.00\% = 0.07$, $82.58\%=0.8258$
Step2: Calculate weighted - value for each isotope
For isotope 1: $13.913\times0.0056 = 0.0779128$
For isotope 2: $15.909\times0.0986=1.5686274$
For isotope 3: $16.909\times0.07 = 1.18363$
For isotope 4: $17.500\times0.8258 = 14.4515$
Step3: Sum up the weighted - values
$0.0779128+1.5686274 + 1.18363+14.4515=17.2816702\approx17.28$
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17.28