Question

multiple choice 20 points a particular type of cell doubles in number every hour. which function can be used to find the number of cells present at the end of h hours if there are initially 4 of these cells? n = 4(2)^h n = 4+(2)^h n = 4(1/2)^h n = 4+(1/2)^h

Explanation:

Step1: Identify growth - type

The cell number doubles every hour, which is an exponential - growth situation. The general formula for exponential growth is $n = n_0\times r^h$, where $n_0$ is the initial amount, $r$ is the growth factor, and $h$ is the number of time - intervals.

Step2: Determine values

Here, the initial number of cells $n_0 = 4$, and the growth factor $r = 2$ (since the number of cells doubles every hour), and the number of hours is $h$.

Step3: Write the formula

Substituting the values into the formula, we get $n=4\times(2)^h$.

Answer:

$n = 4(2)^h$