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Question
3 multiple choice 2 points imagine you are performing a cross involving seed color in garden pea plants. what f1 offspring would you expect if you cross true - breeding parents with green seeds and yellow seeds? yellow seed color is dominant over green. 75% green seeds and 25% yellow seeds 100% yellow seeds 100% yellow - green seeds 75% yellow seeds and 25% green seeds 4 multiple choice 2 points curly hair is dominant to straight hair. the heterozygote is wavy. shari has curly hair and marries george who has straight hair. what is the chance that their child will have wavy hair? use a punnett square to determine the answer. 75% 100% 0% 50% 25% 5 multiple choice 2 points a test cross involving two traits, such as seed color and seed texture is called a(n) ______ cross. polygenic trihybrid monohybrid dihybrid
Question 3
Step1: Define alleles
Let Y represent the allele for yellow (dominant) and y for green (recessive). True - breeding parents are YY (yellow) and yy (green).
Step2: Determine gametes
The YY parent produces Y gametes and the yy parent produces y gametes.
Step3: Analyze F1 generation
When Y and y gametes combine, all F1 offspring have the genotype Yy. Since yellow is dominant, all F1 offspring have yellow seeds.
Step1: Define alleles
Let C represent the allele for curly hair (dominant) and c for straight hair (recessive). Shari has curly hair (CC or Cc), George has straight hair (cc). Since the heterozygote is wavy, we assume Shari is Cc.
Step2: Set up Punnett - square
| C | c | |
|---|---|---|
| c | Cc | cc |
Step3: Calculate probability
Half of the offspring have the genotype Cc (wavy hair). So the probability is 50%.
A cross involving two traits is called a dihybrid cross. A polygenic cross involves multiple genes contributing to a single trait, a trihybrid cross involves three traits, and a monohybrid cross involves one trait.
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100% yellow seeds