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multiply the polynomials. $(4w - 1)(5w^{2}+w + 1)=square$

Question

multiply the polynomials.
$(4w - 1)(5w^{2}+w + 1)=square$

Explanation:

Step1: Apply distributive property

$(4w - 1)(5w^{2}+w + 1)=4w(5w^{2}+w + 1)-1(5w^{2}+w + 1)$

Step2: Multiply each term

$4w(5w^{2}+w + 1)=4w\times5w^{2}+4w\times w+4w\times1 = 20w^{3}+4w^{2}+4w$
$-1(5w^{2}+w + 1)=-5w^{2}-w - 1$

Step3: Combine like - terms

$(20w^{3}+4w^{2}+4w)+(-5w^{2}-w - 1)=20w^{3}+(4w^{2}-5w^{2})+(4w - w)-1=20w^{3}-w^{2}+3w - 1$

Answer:

$20w^{3}-w^{2}+3w - 1$