Question

multiply.
$(5y - 1)(6y^2 - 7y - 4)$
simplify your answer.
$square$

Explanation:

Step1: Apply distributive property

Multiply \(5y\) and \(-1\) with each term in \((6y^{2}-7y - 4)\) separately.
First, \(5y\times(6y^{2}-7y - 4)=5y\times6y^{2}-5y\times7y-5y\times4 = 30y^{3}-35y^{2}-20y\)
Second, \(-1\times(6y^{2}-7y - 4)=-1\times6y^{2}+(-1)\times(-7y)+(-1)\times(-4)=-6y^{2}+7y + 4\)

Step2: Combine like terms

Add the two results from Step 1:
\((30y^{3}-35y^{2}-20y)+(-6y^{2}+7y + 4)\)
Combine the \(y^{2}\) terms: \(-35y^{2}-6y^{2}=-41y^{2}\)
Combine the \(y\) terms: \(-20y + 7y=-13y\)
So the simplified form is \(30y^{3}-41y^{2}-13y + 4\)

Answer:

\(30y^{3}-41y^{2}-13y + 4\)