Question

nacl tiene una . ¿cuál es la masa de una muestra de que necesita de calor para fundirse completamente? use h. $delta h_{fus}=30.2 kj/mol$ nacl732.6 kj $q = ndelta h$ 1,417.7 g 24.3 g 82.7 g 1,407.1 g

Explanation:

Step1: Rearrange the heat - moles formula

Given $q = n\Delta H$, we can solve for the number of moles $n$. Rearranging gives $n=\frac{q}{\Delta H}$. We know that $q = 732.6\ kJ$ and $\Delta H=30.2\ kJ/mol$. So, $n=\frac{732.6\ kJ}{30.2\ kJ/mol}=24.26\ mol$.

Step2: Calculate the molar mass of NaCl

The molar mass of Na (sodium) is approximately $22.99\ g/mol$ and the molar mass of Cl (chlorine) is approximately $35.45\ g/mol$. The molar mass of NaCl, $M = 22.99\ g/mol+35.45\ g/mol = 58.44\ g/mol$.

Step3: Calculate the mass of NaCl

Using the formula $m = n\times M$, where $n = 24.26\ mol$ and $M = 58.44\ g/mol$. So, $m=24.26\ mol\times58.44\ g/mol\approx1417.7\ g$.

Answer:

1,417.7 g